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(20pts) A proton collides with an identical proton that is initially at rest. The incoming proton has an initial speed of 3.50 x 105
(20pts) A proton collides with an identical proton that is initially at rest. The incoming proton has an initial speed of 3.50 x 105 m/s and makes a glancing collision with the second proton. After impact, the first proton moves with a speed of 2.80 x 105 m/s at an angle of 37.0 to the original direction of motion and the second proton deflects at an angle of to the same axis. The proton mass is 1.67 x 10.27 kg. 3 (a) Write the equations expressing conservation of linear momentum. (6pts) (b) Find the final velocity of the second proton. (7pts) (c) Calculate the change in kinetic energy for each proton. Compare the values you get for each proton and explain the result. (5pts) (d) What is the angle between the two final velocities of the two protons? What could you conclude about this result? (2pts) Before the collision After the collision rest M2 1-7.88x10 37.2 -73 M>=1.67x10
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a Conservation of linear momentum in the xdirection m1v1i m2v2i m1v1fcostheta m2v2fcosphi Conservati...Get Instant Access to Expert-Tailored Solutions
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