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#21 A 2018 poll of 3633 randomly selected users of a social media site found that 1645 get most of their news about world events
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A 2018 poll of 3633 randomly selected users of a social media site found that 1645 get most of their news about world events on the site. Research done in 2013 found that only 45% of all the site users reported getting their news about world events on this site. a. Does this sample give evidence that the proportion of site users who get their world news on this site has changed since 2013? Carry out a hypothesis test and use a 0.05 signicance level. b. After conducting the hypothesis test, a further question one might ask is what proportion of all of the site users get most of their news about world events on the site in 2018. Use the sample data to construct a 95% condence interval for the population proportion. How does your condence interval support your hypothesis test conclusion? a. State the null and alternative hypotheses. Let p be the proportion of site users who get their world news on the site. (Type integers or decimals. Do not round.) Compute the ztest statistic. FD (Round to two decimal places as needed.) Compute the pvalue. pvalue = D (Round to three decimal places as needed.) Reject Ho or do not reject Ho and interpret the conclusion. Choose the correct answer below. O A. Do not reject Ho. The percentage is not significantly different from 45%. O B. Reject Ho. The percentage is not significantly different from 45%. O C. Reject Ho. The percentage is significantly different from 45%. O D. Do not reject Ho. The percentage is significantly different from 45%. b. The 95% confidence interval for the population proportion is (Round to four decimal places as needed.) The result of the 95% confidence interval with the result of the hypothesis test performed in part (a) because the value of Po is the 95% confidence interval.A researcher carried out a hypothesis test using a twotailed alternative hypothesis. Which of the following zscores is associated with the smallest pvalue? Explain. i.z= 0.32 ii.z=1.74 iii.z= 1.94 iv.z= 2.96 E) Which zscore has the smallest pvalue? OA. z=1.94 OB. 2:1.74 0c. z=O.32 OD. z=-2.96 Explain. O A. The zscore closest to 0 has the largest tail area and thus has the smallest p-value. O B. The zscore farthest from 1 has the largest tail area and thus has the smallest pvalue. O C. The zscore farthest from 0 has the smallest tail area and thus has the smallest pvalue. O D. The zscore closest to 0 has the smallest tail area and thus has the smallest pvalue. A study for the treatment of patients with HIV-1 was a randomized, controlled, double-blind study that compared the effectiveness of ritonavir-boosted darunavir (rbd), the drug currently used to treat HIV-1, with dorovirine, a newly developed drug. Of the 373 subjects taking ritonavir-boosted darunavir, 311 achieved a positive result. Of the 373 subjects taking dorovirine, 328 achieved a positive result. Complete parts (a) and (b). . . . a. Find the sample percentage of subjects who achieved a positive outcome in each group. The sample percentage of subjects who achieve a positive outcome with ritonavir-boosted darunavir is %. The sample percentage of subjects who achieve a positive outcome with dorovirine is %. (Round to two decimal places as needed.) b. Perform a hypothesis test to test whether the proportion of patients who achieve a positive outcome with the current treatment (ritonavir-boosted darunavir) is less than the proportion of patients who achieve a positive outcome with the new treatment (dorovirine). Use a significance level of 0.01. Analyze the results and determine if dorovirine is a more effective treatment for HIV-1 than ritonavir-boosted darunavir. Consider population 1 to be the ritonavir-boosted darunavir with the proportion of positive outcomes p, and population 2 to be the dorovirine with the proportion of positive outcomes p2. What are the null and alternative hypotheses for the hypothesis test? O A. Ho: P1 P2 Ha: P1 = P2 Ha: P1 > P2 Ha: P1 = P2Identify the test statistic. z = (Round to two decimal places as needed.) Identify the pva|ue. p-value = (Round to three decimal places as needed.) Since the p-value is 7 the signicance level of a: 0.01, ? the null hypothesis. There is V evidence to support the claim that the percentage from the ritonavirboosted darunavir group is 7 the percentage from the dorovirine group. Analyze the results. 5 dorovirine a more effective treatment for HIV1 than ritonavirboosted darunavir? Why or why not? O A. No, since the decision of the test was to fail to reject the null hypothesis of no difference. 0 B. Yes, since the decision of the test was to reject the null hypothesis of no difference. 0 C. No; although the decision of the test was to reject the null hypothesis of no difference, it cannot be concluded that one treatment is better than the otherit can only be concluded that they are different. 0 D. Yes, since the decision of the test was to fail to reject the null hypothesis of the proportion from the ritonavir-boosted darunavir group being greater than the proportion of the dorovirine groupStep by Step Solution
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