21:25 4 Outlook Gereed Practise_test_TTO4_Mec... .Ill '5' [E' Q we 9 =>> 9.80 ms2 I Accept 9.81, ara plain \"g\" Ignore sign if pro vided. 9d. Draw. on the axes, a graph to show the variation with time of the height [1 mark] of the ball from the instant it rebounds from the floor until the instant it reaches the maximum rebound height. No numbers are required on the axes. heign time Markscheme concave down parabola as shown with nonzero initial slope and zero final slope J Award [1] mark if curve starts from a positive time value. Award [0] if the nal slope is negative. 10. The graph shows how the position of an object varies with time in the [1 mark] interval from 0 to 3 s. position/m 4 21:31 D. The component of the normal reaction at the surface parallel to the plane 18 van 18rkscheme 22. Three forces act at a point. In which diagram is the point in equilibrium? [1 mark] A. B F2 F. C. D F2 F, Markscheme B International Baccalaureate Organization 2022 International Baccalaureate Baccalaureat International International Baccalaureate @ - Baccalaureat International@ - Bachillerato Internacional Bachillerato Internacional Printed for MAARTENS CLG INTL SCH a cdnp.prod.managebac.com21231 .Ill '5' [E' 19. The variation with time tof the acceleration a of an object is shown. [1 mark] 3.0 2.0 a I rn 5-2 1.0 Us What is the change in velocity of the object from t: 0 to t: 6 s? A. 6 m 5-1 B. 8 m 5'1 C. 10 m 5-1 D. 14 m 5'1 Markscheme C 20. 21. A climber of mass m slides down a vertical rope with an average [1 mark] acceleration a. What is the average frictional force exerted by the rope on the climber? A. mg B. mig + a) C. mlg - a) D. ma Markscheme C A cube slides down the surface of a ramp at a constant velocity. What is [1 mark] the magnitude of the frictional force that acts on the cube due to the surface? A. The weight of the cube B. The component of weight of the cube parallel to the plane C. The component of weight of the cube perpendicular to the plane D. The component of the normal reaction at the surface parallel to the plane Markscheme B E cdnp.prod.managebac.com CD > 6 m 21130 a" "5" C} 15 van 18 Markscheme B Distance is area under the graph. P:2*20*1/2+5*20=20+100=120m Q: 8 *40 *1/2 = 160 m Difference 160 -120 = 40 m 17. Three forces act on a block which is sliding down a slope at constant [1 mark] speed. W is the weight, R is the reaction force at the surface of the block and F is the friction force acting on the block. R In this situation A. there must be an unbalanced force down the plane. B. W = R. C. F = W. D. the resultant force on the block is zero. Markscheme D 18. Two forces act along a straight line on an object that is initially at rest. [1 mark] One force is constant; the second force is in the opposite direction and proportional to the velocity of the object. varying force constant [area (9) object What is correct about the motion of the object? A. The acceleration increases from zero to a maximum. B. The acceleration increases from zero to a maximum and then decreases. C. The velocity increases from zero to a maximum. D. The velocity increases from zero to a maximum and then decreases. Markscheme C 19. The variation with time tof the acceleration a of an object is shown. [1 mark] B cdnp.prod.managebac.com 2195 ..u a @- 4 Outlook Gereed Practise_test_TTO4_Mec... Q L. 50017] D. 6000 m Markscheme C final PE = mgh Gaining potential energy (so climbing) with a rate of 6000W, this is 6000J/s. It takes 20 minutes, so 20*60 = 1200 seconds. E = P*t = 6000*1200 = 7.200.000] Final PE = 7.200.000] h = 7.200.000 /(10*1200) = 600 m 12. Two identical boxes are stored in a warehouse as shown in the diagram. [1 mark] Two forces acting on the top box and two forces acting on the bottom box are shown. Which is a force pair according to Newton's third law? A. 1 and 2 B. 3and4 C. 2and3 D. 2 and4 Markscheme C 13. A person with a weight of 600 N stands on a scale in an elevator. Use 9 = [1 mark] 10 m/sZ. elevator scale What is the acceleration of the elevator when the scale reads 900 N? A. 5. 0 1115'2 downwards B. 1. 5 ms'2 downwards C. 1. 5 ms'2 upwards D. 5. 0 ms'2 upwards 21130 a" "5" C} in: giuyu any": Ln: vuiiuuuu nu.\" um: Lul Lllc VEIULILy v on Lil: uuu. nu resistance is negligible. Take g = 9.80 m 5'2. The ball reaches the floor after 1.0 s. 93. Determine H. [1 mark] Markscheme H= %gt'2 = 4.9 m ./ Accept other methods as area from graph, alternative kinematics equations or conservation of mechanical energy. Award [1] fora bald correct answer in the range 4.9 - 5.1. Award [0] if time used is different than 1.05. 9b. Label the time and velocity graph, using the letter M, the point where the [1 mark] ball reaches the maximum rebound height. Markscheme Mat1.65./ 9c. State the acceleration of the ball at the maximum rebound height. [1 mark] Markscheme g = 9.80 ms1 I n I: Accept 9.81, or a plain g . Ignore sign if pro Vided. 9d. Draw, on the axes, a graph to show the variation with time of the height [1 mark] of the ball from the instant it rebounds from the floor until the instant it reaches the maximum rebound height. No numbers are required on the axes. height E cdnp.prod.managebac.com G 6 m 21130 a" '5' [E' A. 0.6m 12 van 18 Markscheme C final PE = mgh Gaining potential energy (50 Climbing) with a rate of 6000W, this is 60001/5. It takes 20 minutes, so 20*60 = 1200 seconds. E = P*l: = 6000*1200 = 7.200.000] Final PE = 7.200.000] h = 7.200.000 l(10*1200) = 600 m 12. Two identical boxes are stored in a warehouse as shown in the diagram. [1 mark] 13. Two forces acting on the top box and two forces acting on the bottom box are shown. Which is a force pair according to Newton's third law? A. 1 and 2 B. 3 and4 C. 2 and 3 D. 2 and4 Markscheme C A person with a weight of 600 N stands on a scale in an elevator. Use 9 = [1 mark] 10 m/sZ. elevator Scale What is the acceleration of the elevator when the scale reads 900 N? A. 5. 0 ms'2 downwards B. 1. 5 ms'2 downwards C. 1. 5 ms'2 upwards D . 5.0 ms2 upwards H cdnp.prod.managebac.com CD > 6 m