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22) [5] Use the substitution: 1 = 7x5+3 to rewrite the integral below completely in terms of u and du : Jx54 sin ( 7x5

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22) [5] Use the substitution: 1 = 7x5+3 to rewrite the integral below completely in terms of u and du : Jx54 sin ( 7x5 + 3) dix = 23) [5] Given: f'(x) = 3x2, f(2)=1917 Use antiderivatives to find f(x)

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