22 DETAILS MY NOTES ASK YOUR TEACHER Object Height. Suppose an object is thrown straight up from the ground. The height after & seconds is given by the formula h(t) = -4t+ 79tz+ 240 (a) The time in seconds when the object reached the highest point was Note: Round to 4 digits after the decimal point, if rounding is required O 9.875 s 29.625 5 None of the other answers 240 s 13.1667 s Oos (b) The height is maximized at the critical point x = a because the second derivative test found Of" (a ) > 0 Of (a ) = 0 Of(a) was negative to the left of x = a and positive to the right Of(a) was positive to the left of x = a and negative to the right Of (a )