22 Suppose fis continuous on [5,22] and f(t) dt = -3. Compute each of the following values 15 13 (a) f(t) dt = /13 5 f(t ) dt = 22 (c ) 4f(t) dt = 5 22 (d) f(t ) + 4 dt = 15 13 -22 (e) f(t ) dt + f(t) dt = 15 13 (f) The average value of f(x) on [5,22] =