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#23answer a-c (4%) Problem 23: A uniform rod of mass M and length L is free to swing back and forth by pivoting a distance

#23answer a-c

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(4%) Problem 23: A uniform rod of mass M and length L is free to swing back and forth by pivoting a distance x from its center. It undergoes harmonic oscillations by swinging back and forth under the influence of gravity. Randomized Variables M =4.6 kg L = 13 m x = 0.42 m Forbes, David - david.forbes@doane.edu @theexpertta.com - tracking id: 9N69-72-B9-45-AB7A-40021. In accordance with Expert TA's Terms of Service. copying this information to any solutions sharing website is strictly forbidden. Doing so may result in termination of your Expert TA Account. D A 33% Part (a) In terms of M, L, and x, what is the rod's moment of inertia / about the pivot point. I= 1 Grade Summary Deductions 0% Potential 100% B 0 7 8 9 HOME Submissions a d g 4 5 6 Attempts remaining: 999 (0% per attempt) h K 2 3 detailed view L M n + 0 P t X VO BACKSPACE Submit Hint Feedback I give up! Hints: 0% deduction per hint. Hints remaining: 2 Feedback: 0% deduction per feedback. 4 33% Part (b) Calculate the rod's period T in seconds for small oscillations about its pivot point. A 33% Part (c) In terms of L, find an expression for the distance xm for which the period is a minimum

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