(25%) Problem 2: A uniform beam of length L and mass M has its lower end pivoted at P on the floor, ta making an angle 0 with the floor. A horizontal cable is attached at its upper end B to a point A on a wall. A box of mass M is suspended from a rope that is attached to the beam one-fourth L from its upper end. EXPEL M Assignment Status Click here for . e detailed view Otheexpertta.com Problem Status Completed Parti WN Completed -25% Part (a) Write an expression for the y-component Py of the force exerted by the pivot on the beam. Completed Py = 2Mg Correct! 25% Part (b) Write an expression for the tension T in the horizontal cable AB T = ( M g 0.5 cos(0) + Mg (3/4 ) cos(0) )/sin(0) Correct! 25% Part (c) Write an expression for the x-component Px of the force exerted by the pivot on the beam, in terms of T. Px = T Correct! *25% Part (d) What is the tension in the horizontal cable, in newtons, if the mass of the beam is 39 kg, the length of the beam is 15 m, and the angle is 42? T = 456.02 Grade Summary Deductions 0% Potential 100% sin() cos() tan () JE ( ) 7 8 9 HOME Submissions cotan() asin() acos() E 1 4 4 5 6 Attempts remaining: 5 0% per attempt) atan( ) acotan( ) sinh() 1 * 1 2 3 detailed view cosh( tanh() cotanh() 0 END 10% 0% Degrees O Radians VO BACKSPACE DEL. CLEAR AWN 0% 0% Submit Hint I give up! Hints: 1% deduction per hint. Hints remaining: 1 Feedback: 0% deduction per feedback Submission History All Date times are displayed in Pacific Standard Time Red submission date times indicate late work. Date Time Answer Hints Feedback 1 Apr 09, 2023 6:29 PM T = 477.414 T=477.4 2 Apr 13, 2023 11:20 AM T = 208.49 Note: Feedback not accessed. T = 208.5 Apr 13, 2023 11:45 AM T = 175.1 4 Apr 13, 2023 11:49 AM T = 460.37 T = 460.4 Apr 13, 2023 11:53 AM T = 456.02 T = 456.0 All content @2023 Expert TA, LLC