2.6 Extend the calculation of the falling particle on the rotating earth by solving Eq. (11.8) to second order in w. Show that the time to fall a vertical distance h is increased by two(2h/9) /2 sin e and that the particle is deflected toward the equator by an amount (w2h2/39) sin 20.mr = mg - 2mo x i (11.8) (up) F (east ) x (south)