2.(a) Place the following 7 data bits 1001100 in their correct positions in the 11 bit Hamming code (R8, R4, R2 and R1 are the parity bits and do not form part of the data):

11 10 9 8 7 6 5 4 3 2 1

R2

11	10	9	8	7	6	5	4	3	2	1
			Rs				R4		R2	R1

(b) Show for each parity bit, which bits are covered by that parity bit. The answer for parity bit 1 has been provided:

Parity bit R1 covers bits: 1, 3, 5, 7, 9, 11

Parity bit R2 covers bits:

Parity bit R4 covers bits: Parity bit R8 covers bits:

(c) Calculate the 4 parity bits. Assume odd parity is used: The value of parity bit R1 is:

The value of parity bit R2 is:

The value of parity bit R4 is:

The value of parity bit R8 is:

3.Given the following 11 bit Hamming code with the data bits 1011010:

11 10 9 8 7 6 5 4 3 2 1

11	10	9	8	7	6	5	4	3	2	1
1	0	1	0	1	0	1	1	0	1	0

a. Which parity bits have the correct value if even parity is used:

Parity bit 1 is correct: yes / no

Parity bit 2 is correct: yes / no

Parity bit 4 is correct: yes / no

Parity bit 8 is correct: yes / no

b. Which bit of the 11 bit Hamming code is wrong?

Answer:

c. Rewrite the data and parity bits using the corrected value:

11 10 9 8 7 6 5 4 3 2 1

11

10

9

8

7

6

5

4

3

2

1

4,Explain the differences between register memory, main memory, and secondary memory.