Question
2Cr + 1.5 O2 = Cr2O3; DG = -1,110,100 + 247.3 T (joules) CO + 0.5 O2 = CO2; DG = -282,400 + 86.81 T
2Cr + 1.5 O2 = Cr2O3; DG = -1,110,100 + 247.3 T (joules) CO + 0.5 O2 = CO2; DG = -282,400 + 86.81 T (joules) H2 + 0.5 O2 = H2O; DG = -247,500 + 55.85 T (joules)
If your boss says, "dont use hydrogen pressure greater than 1 atm (i.e. no bombs)", Could you use C to reduce Chrome oxide? Explain why or why not?
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Thermodynamics for Engineers
Authors: Kenneth A. Kroos, Merle C. Potter
1st edition
1133112862, 978-113311286
