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2V (1/2) + X DH1 = 10 kJ/mol (3/2) + 4X 2V + x + 3Y DH2 = -30 kJ/mol Z + 4V - X

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2V (1/2) + X DH1 = 10 kJ/mol (3/2) + 4X 2V + x + 3Y DH2 = -30 kJ/mol Z + 4V - X DH3 = 20 kJ/mol Calculate DH for: X-Z + 3Y Select one: O a. 10 kJ/mol b. 0 kJ/mol OC-20 kJ/mol d.-10 kJ/mol e. 20 kJ/mol

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