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(2x+y)+2xy=0, is dx off between origin and tanger abscissa of point of contact is + y+c)=0 --)=0 -)=0 -)=0 =(x+1)ft.y(t)dt,x>0, is kx3 (1) y==

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(2x+y)+2xy=0, is dx off between origin and tanger abscissa of point of contact is + y+c)=0 --)=0 -)=0 -)=0 =(x+1)ft.y(t)dt,x>0, is kx3 (1) y== +C 3+ -kx3 (2) y=- +CX 2 -kx2 kx3 cx2 (4) y= 3 = + 2 (3) y=- +C 2 15. A curve y = f(x) passes through point P(1, 1). The normal to curve at point P is a(y-1)+(x-1)=0. If slope of tangent at any point on curve is proportional to ordinate at that point, then equation of curve is (1) y=eax-1 (2) y=eax +1 (3) y=eax +a (4) y = ea(x-1) (2) y= C er 4) cxex slope of tangent at any 1. of the abscissa to the SECTION - B Objective Type Questions (One or more than one option(s) is/are correct) The foci of the curve which satisfies the equation (1+ y)dx-xy dy = 0 and passes through the point (1,0) are (1) (2, 0) (2) (0, 2) (3) (-2, 0) (4) (0,-2) 2. 8 St The general solution of the equation, dy X = y.In(y/x) is dx ercepts of a tangent at double of the x and y ESA 3. (1) y = xet - cx (2) y = xe1+ + CX (3) y = xe.ex (4) y = xecx The equation of the curve passing through (3, 4) and satisfying the differential equation, e of whose tangent at hich passes through 2 dy y +(x-y) dy-x=0 can be dx dx

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