3. [-/1 Points] DETAILS LARPCALC10 4.8.008. MY NOTES Solve the right triangle shown in the figure for all unknown sides and angles. Round your answers to two decimal places. A = 6.60, a = 44.5 B = O C = O b = C = B C a C b A Need Help? Read It Watch ItMY NO 4. [-/1 Points] DETAILS LARPCALC10 4.8.012. Solve the right triangle shown in the figure for all unknown sides and angles. Round your answers to two decimal places. b = 1.84, c = 9.59 A = B = O o C = a = B C a C b A Need Help? Read It Watch It5. [-/1 Points] DETAILS LARPCALC10 4.8.014.MI.SA. MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive any points for the skipped part, and you will not be able to come back to the skipped part. Tutorial Exercise Find the altitude of the isosceles triangle shown in the figure. 0 = 130, b = 7 Step 1 Let h be the altitude of the isosceles triangle. Recall that the altitude of an isosceles triangle is the perpendicular bisector drawn to its base. The length of the base of the isosceles triangle is b = Submit Skip (you cannot come back)6. [-/1 Points] DETAILS LARPCALC10 4.8.019. MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER A ladder that is 30 feet long leans against the side of a house. The angle of elevation of the ladder is 85. Find the height from the top of the ladder to the ground. (Round your answer to one decimal place.) ft Need new ii 1. [-/1 Points] DETAILS LARPCALC10 4.8.023. MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER A passenger in an airplane at an altitude of 10 kilometers sees two towns directly to the east of the plane. The angles of depression to the towns are 29 and 55 (see gure). How far apart are the towns? (Round your answer to one decimal place.) km 8. [-/1 Points] LARPCALC10 4.8.027.MI.SA. ASK YOUR TEACHER PRACTICE ANOTHER This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive any poinB for the skipped part, and you will not be able to come back to the skipped part. Tutorial Exercise A Global Positioning System satellite orbits d = 18,500 miles above Earth's surface (see gure). Find the angle of depression from the satellite to the horizon. Assume the radius of Earth is 4000 miles. GPS satellite Angle of / depression The GPS satellite is 18,500 miles above Earth's surface. We assume that the radius of Earth is 4000 miles. So, the distance of the GPS satellite from the center of Earth will be 18,500 + = [:] miles. Submit mu cannot come back) 9. [-/1 Points] LARPCALC10 4.8.031. ASK YOUR TEACHER PRACTICE ANOTHER A police department has set up a speed enforcement zone on a straight length of highway. A patrol car is parked parallel to the zone, 200 feet from one end and 150 feet from the other end (see gure). (a) Find the length I of the zone and the measures of the angles A and B (in degrees). (Round your answers to two decimal places.) I = ft _ o 3: (b) Find the minimum amount of time (in seconds) it takes for a vehicle to pass through the zone without exceeding the posted speed limit of 45 miles per hour. (Round your answer to two decimal places.) sec Need Help? ii 1o. [0.17/1 Points] PREVIOUS ANSWERS LARPCALC1O 4.8.046.M|.SA. ASK YOUR TEACHER PRACTICE ANOTHER This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive any points for the skipped part, and you will not be able to come back to the skipped part Tutorial Exercise Find a model for simple harmonic motion satisfying the specied conditions. Displacement, d Amplitude, a Period (f = 0) 0 3.4 meters 8 seconds Step 1 The displacement d is O at (t = 0). Therefore we use the equation d = a- J E: sin(wt) Submit uxou cannot come back) 11. [-/1 Points] DETAILS LARPCALC10 4.8.052. MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER For the simple harmonic motion described by the trigonometric function, find the maximum displacement, the frequency, the value of d when t = 3 and the least positive value of t for which d = 0. Use a graphing utility to verify your results. d = _ cos 24xt (a) Find the maximum displacement. (b) Find the frequency. cycles per unit of time (c) Find the value of d when t = 3. d = (d) Find the least positive value of t for which d = 0. t = Need Help? Read It12. [-/1 Points] LARPCALC10 4.8.056. ASK YOUR TEACHER The number of hours H of daylight in Denver, Colorado, on the 15th of each month starting with January are: 9.68, 10.72, 11.92, 13.25, 14.35, 14.97, 14.72, 13.73, 12.47, 11.18, 10.00, and 9.37. A model for the data is H(t) = 12.13 + 2.77 Sin(%t 1.60) where t represents the month, with t = 1 corresponding to January.+ (a) Use a graphing utility to graph the data points and the model in the same viewing window. H(t) H\") 15 '0 10 , .._1_.._._1._._._i._._.i_._..L...i.._t O 2 4 6 8 10 12 H(t) H\") 15 '0 10 t .._._.._._.._._._._._._._._.._._..._.._t O 2 4 6 8 10 12 O 2 4 6 8 10 12 (b) What is the period of the model? :1 Is it what you expected? Explain. 0 Yes, this is the expected value because there are 12 months in one year. 0 Yes, this is the expected value because it corresponds to the number of data points. 0 No, this is not the expected value because there are 12 months in one year. 0 No, this is not the expected value because there are four seasons in one year. O No, this is not expected because this data is only representative of one year. (c) What is the amplitude of the model? :1 What does it represent in the context of the problem? 0 The amplitude represents the average displacement from the average number of hours of daylight. O The amplitude represents the maximum displacement from the average number of hours of daylight. O The amplitude represents the average number of hours of daylight. O The amplitude represents the maximum hours of daylight. O The amplitude represents the minimum hours of daylight. Need Help