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3. [1l2 Points] PREVIOUS ANSWERS A meter stick with a mass of 0.87 kg is held perpendicular to a vertical wall by a cord of

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3. [1l2 Points] PREVIOUS ANSWERS A meter stick with a mass of 0.87 kg is held perpendicular to a vertical wall by a cord of length d = 3.3 m attached to the end of the meter stick and also to the wall above the other end of the meter stick. (a) Determine the tension in the cord. 43 X Where is a good point about which to take the torques? Which condition of equilibrium will allow us to write an expression that will allow us to determine the tension in the cord? See if you can obtain an expression for the tension T in the cord in terms of the mass m of the meter stick, the acceleration due to gravity 9, and the angle 9 between the direction of the force and displacement vector. Be careful which angle you use when writing an expression for the torque due to the tension in the cord. N (b) Will the tension in the cord will be greater than, less than, or the same as that found in part (a) if the string is shortened? To clarify, when the string is shortened, the location where the string is attachec to the wall is lowered so that the meter stick remains horizontal. o greater than less than the same as J Submit Answer 4. [1/3 Points] PREVIOUS ANSWERS WEBASSIGNALGPHYS1 9.4.005. A uniform rod is attached to a wall by a hinge at its base. The rod has a mass of 2.0 kg, a length of 1.3 m, is at an angle of 35 above the horizontal, and is held in place by a horizontal cord attached to the other end of the rod and bolted to the wall above the base of the rod. (a) Determine the tension in the cord. 563 X Where is a convenient point about which to take the torques? See if you can write an expression for the torque in terms of the force producing the torque and the perpendicular distance from the line of action of the force to the point about which we have specified to determine the torque. See if you can write a second condition of equilibrium that will allow you to determine the tension in the cord. N (b) Determine the horizontal and vertical components of the force exerted on the rod by the hinge. 5.63 x FH = Now that you know the tension in the cord from part (a), see if you can write a rst condition of equilibrium statement that will allow you to determine the horizontal component of the force exerted on the rod by the hinge. N FV= 19.62 y N Supporting Materials

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