3. (25 points) In an experiment studying inhibitors for a biological side reaction which competes with the desired reaction, the following side product concentration C. data was determined in the lab at specific inhibitor concentrations: Inhibitor Conc. % Side Product (Cu) gmol/ml 0.1 0.5 1.0 1.5 2.0 2.5 3.0 4.0 7000 5900 4900 3700 2800 2100 1500 500 A) Fit a third order polynomial to the above data using polyfit and print the resulting equation in the form: The third order equation is Cu = ****I^3 + **** I^2 + **** I+ **** B) The reaction rater (gmol/ml-min) for the desired reaction is: ka Cd 1.5 - kucu 1 + kdCd + kuu re The rate constant for the desired products production is ka=0.045 min? The rate constant for the side products production is ke=0.006 min Set up a loop and use the results of part A along with polyval and the secant method to find the desired concentration Ca for the following inhibitor concentrations: 0.2%, 0.8%, 1.4% 2.0%, 2.6% and 3.2% to obtain a rate equal to 3.0 gmol/ml-min. You can set Cd = 200 as your initial guess for the first inhibitor concentration and then your previous solution in subsequent initial guesses