3. [-/5 Points] DETAILS A Exam 4 - TMTH 3360-2 (20948), section. MENDSTAT14 7.E.045. Homework Help - Q&A from Online Tutor. Online Assignments An advertiser claims that the average percentage of brown M&M'S candies in a package of milk chocolate M&M'S is 14%. Suppose you randomly select a package of milk chocolate M&M'S that contains 57 candies and determine the proportion of brown candies in the package. (a) What is the approximate distribution of the sample proportion of brown candies in a package that contains 57 candies? MY NOTES ASK YOUR TEACHER The distribution is binomial and cannot be approximated. The distribution is approximated by a normal distribution with mean 14 and standard deviation 0.0460. The distribution is approximated by a normal distribution with mean 0.14 and standard deviation 0.86. The distribution is approximated by a normal distribution with mean 8.0 and standard deviation 798. The distribution is approximated by a normal distribution with mean 0.14 and standard deviation 0.0460. (b) What is the probability that the sample percentage of brown candies is less than 22%? (Round your answer to four decimal places.) (c) What is the probability that the sample percentage exceeds 34%? (Round your answer to four decimal places.) to (d) Within what range would you expect the sample proportion to lie about 95% of the time? (Round your answers to two decimal places.) You may need to use the appropriate appendix table or technology to answer this question. 4. [-/5 Points] DETAILS MENDSTAT14 7.E.049. MY NOTES ASK YOUR TEACHER The sample means were calculated for 40 samples of size n = 5 for a process that was judged to be in control. The means of the 40 values and the standard deviation of the combined 200 measurements were x = 159.5 and s = 4.6, respectively. UCL = (a) Use the data to determine the upper and lower control limits for an x chart. (Round your answers to two decimal places.) LCL = (b) Construct an x chart for the process. Sample Sample Sample Mean Sample Mean Mean Mean 180 180 180 180 170 170 UCL 170 170 160 160 160 UCL 160 150 150 LCI. 150 150 LCL 140 140 140 LCI 140 LCL. 130 130 130 130 Sample Sample sample Explain how the chart can be used. Values of x are plotted and should remain outside the range between the UCL and LCL. If not, the process should be checked. Values of x are plotted and should remain between the center line and LCL. If not, the process should be checked. Values of x are plotted and should remain between the UCL and center line. If not, the process should be checked. Values of x are plotted and should remain above the UCL. If not, the process should be checked. Values of x are plotted and should remain between the UCL and LCL. If not, the process should be checked. 24,972 APR 3 W G ELAN5. [-/5 Points] DETAILS MENDSTAT14 7.E.051. Samples of n = 100 items were selected hourly over a 100-hour period, and the sample proportion of defectives was calculated each hour. The mean of the 100 sample proportions was 0.055. (a) Use the data to find the upper and lower control limits for a p chart. (Round your answers to three decimal places.) UCL = LCL = (b) Construct a p chart for the process. Proportion Proportion Proportion Proportion 0.25 0.15 UCL 0.15 0.15 UCL UCL 0.20 UCL 0.10 0.10 0.10 0.15 0.10 0.05 0.05 0.05 0.05 LCL LCL LCL - Day LCL Day Day Day Explain how the chart can be used. Values of p are plotted and should remain between the center line and the UCL. If not, the process should be checked. Values of p are plotted and should remain outside the control limits. If not, the process should be checked. Values of p are plotted and should remain within the control limits. If not, the process should be checked. Values of p are plotted and should remain below the center line. If not, the process should be checked. Values of p are plotted and should remain between the center line and the LCL. If not, the process should be checked. MENDSTAT14 7.E.053. MY NOTES 40 weeks were x = $10,821 and's = $1408, respectively.), section... Homework Help - Q&A from Online Tutor Online Assignments 1. [-46 Points] DETAILS MENDSTAT14 7.E.015. MAY NOT Random samples of size n were selected from populations with the means and variances given here. Find the mean and standard deviation of the sampling distribution of the sample mean in each case. (Round your answers to four decimal places.) 2:59:25 (8) 1 = 15, N - 15,62-9 (b) n = 100, # = 3, 62=4 (c) n = 10, # = 112, 62 = 1 2. [-/7 Points] DETAILS MENDSTAT14 7.E.019. MY NOTES ASK YOUR TEACHER A random sample of n observations is selected from a population with standard deviation s = 1. Calculate the standard error of the mean (SE) for these values of n. (Round your answers to three decimal places.) (a) n = 1 SE (b) n = 2 SE (c) n = 4 SE = (d) n = 9 SE = (e) n = 16 SE (f) n = 25 SE = (9) n = 100 SE 24,972 APR 1 3[-/5 Points] DETAILS MENDSTAT14 7.E.053. A gambling casino records and plots the mean daily gain or loss from five blackjack tables on an x chart. The overall mean of the sample means and the standard deviation of the combined data over 40 weeks were * = $10,821 and s = $1408, respectively. (a) Construct an x chart for the mean daily gain per blackjack table. Sample Sample Sample Sample Mean Mean Mean Mean 14 000 14000 14 000 14 000 13 000 13 000 UCL UCL UCL 13 000 UCL 13 000 12000 12 000 12 000 12 000 11 000 11 000 11 000 11 000 10 000 10 000 10 000 10 000 LCL 9000 9000 9000 LCL 9000 LCL 8000 LCL 8000 8000 8000 Week Week Week Week (b) How can this x chart be of value to the manager of the casino? The x chart will allow the manager to monitor individual players. The x chart will allow the manager to monitor the blackjack tables to see how many players participate in each game. The x chart will allow the manager to monitor the blackjack tables to see how many face cards are dealt. The x chart will allow the manager to monitor daily gains or losses to predict profits. The x chart will allow the manager to monitor daily gains or losses to see whether there is a problem with any particular table