Question
3 a) Compute the average loss for a process that produces steel shafts. The target value is 6.40 mm and the coefficient is 9500. Eight
3 a) Compute the average loss for a process that produces steel shafts. The target value is 6.40 mm and the coefficient is 9500. Eight samples give 6.36 6.40 6.38 6.39 6.43 6.39 6.46 6.42. b) For an out-of-round condition (smaller-the-better) of a steel shaft, the true indicator readings (TIR) for eight shafts are 0.05 0.04 0.04 0.03 0.04 0.02 0.04 0.03 mm. If the average loss at 0.03 is R150.00, what is the loss function? ii. What is the loss at 0.05? iii. What is the average loss? c) If the specifications are 120 40 for a particular quality characteristic and the average repair cost is R2300, determine the loss function. Determine the loss at y = 120
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