3) A manufacturer of widgets finds that 8% of the widgets are defective when they come off the assembly line. A worker proposes a new assembly technique which he claims will reduce the percentage of defective widgets. His technique is tried on 240 randomly selected widgets and it turns out 13 are defective. Using the Minitab printout below, test to determine if the new assembly technique reduces the percentage of defective widgets. Test at a = 0.01. Show all six steps to receive full credit. Test and Cl for One Proportion: Defective Widgets Method p: event proportion Exact method is used for this analysis. 1 Ho = P = 0:08 Descriptive Statistics 95% Upper Bound D Hi = BLOOB N Event Sample p for p 240 13 0.054167 0.084741 = 0.01 Test Test stownce 0. 05 4 167 Null hypothesis Ho: p = 0.08 Alternative hypothesis H1: p < 0.08 pvalue = 0.08270401 P-Value 0.082 So the test is notsignwhen and we cont rejet the Boy hypothesis