3. An advertisement for the Durham Coffee Company states that the companys large cans contain at least three pounds of coffee, on average. To test the claim or statement in the advertisement, you select a random sample of 16 large cans of coffee from the assembly line. The standard deviation of the amount of coffee in the large cans in the sample equals 0.15 pounds and the average/mean amount of coffee in the large cans in the sample equals 2.92 pounds.

b. If alpha = 0.01, what is the critical value of the associated test statistic?

The part that confuses me Is the end how do I get -1.711, do I subscript on a caulator, If so how do I do that?

b. Let n be the size of sample and df is degree of freedom df =n-1 = 25-1 = 24 It is left tailed test and given a=.05 Critical value is 1.05,24 =-1.711 (Refer t table)