3. How can we find the average molecular weight of air from the mole basis of its major ingredients? 15 Kg charcoal (carbon) was required to burn in presence of 190 kg of air. According to mole basis it was found that, 55% charcoal was converted to carbon dioxide (CO2) and 35% was converted to Carbon monoxide (CO). Find the remaining charcoal amount and average molecular weight of the outlet gas stream. [Ref: 16O, 14N, 12C] [2+4 marks] *