3. If a cup of tea (215. ml, 93.0 C) is cooled by adding an ice cube (22.5 g, -15.0 C), what is the final temperature of the tea? The heat required to melt ice (heat of fusion) is 80.0 cal/g and the specific heat of ice is 0.500 cal/g "C. 180 9 gained ice = - q lost tea gas 100 temperature q -15->0 + q melt + q0->If = - 9 93-If ('C) boiling 00 1 liquid melting 201 20 solid heat absorbed