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# 3 . In the above problem, we assumed that the volume was independent of p ( i . e . , we assumed that

#3. In the above problem, we assumed that the volume was independent of p(i.e., we assumed that =0). In this problem, we remove this assumption by including a nonzero (but you may assume that is independent of p).
(a) Derive an improved expression for G upon an isothermal change in p. The expression should contain only G,, initial and final pressures p0 and p, and the initial volume V0. Hint: start with the definition of , and integrate it under the assumption of constant . This should give you an expression for the volume as a function of pressure, which you can use in your expression for G.
(b) Show that in the limit of small , this expression becomes equal to the expression in Problem #2.
(c) Use your equation in part (a) to repeat the calculation of Problem #2. For water, =4.510-5atm-1. What is the % error when we ignore the compressibility (i.e., how does your answer in prob. 3(c) compare to your answer in prob. 2?)
Info from previous question 100cm^3 of liquid water at 25 C is isothermally compressed from 1 atm to 100 atm
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