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3 'L. Find the area of the surface generated by revolving the curve 3; = 3, 0 s x S- 2, about the x-axis. The

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3 'L. Find the area of the surface generated by revolving the curve 3; = 3, 0 s x S- 2, about the x-axis. The area of the surface is . (Type an exact answer, using 11: as needed.) 0.. Find the area of the surface generated when the given curve is revolved about the x-axis. y = .f4x +1 on [0,2] The area of the generated surface is D square units. (Type an exact answer, using it as needed.) 3 ' 3 Find the area of the surface generated by revolving X=41l1 y, 0 Sys I about the y-axis. 2'4 The area is . (Simplify your answer. Type an exact answer, using TE as needed.) Li: Find the area of the surface generated by 6y + {J- y . . 2 In the Interval 0 s y s In 5 about the y-axis. revolving the curve x = 1115 The area, S, of the surface is given by S = E. (Type an exact answer, using 1: as needed.) \fPut 9 + 2 42 u 4 x do a du 4 Limits when 2 ? 0 the = 9 2 2 2 2 9 + 16 2 25 25 S 2 22 4 25 2 17 Su du 27 x 2 25 2 ( U )\f2 13 2 1I [ 13 1 2 _ 5 3 12 ] W 1 ( 13 1 3 - 5 55 ) Square units W 11 . 9 1\f5 - y dy D Put U 2 5 - y de 2 - dy dy = - du Limits When 0 ) 2 2 17 4 17/ 4 S 2 8n vu - du S on su du 17 1 4

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