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(3 points) It is known that the sequence an = satisfies the conditions of the alternating series test, therefore n! DO the series (-1) converges

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(3 points) It is known that the sequence an = satisfies the conditions of the alternating series test, therefore n! DO the series (-1)" converges to some number _ (you do not need to show this or know its value). n! n=0 (a) What is the smallest number N such that (-1)" M: n! approximates _ with an error less than 0.01? n=0 N (b) Use a calculator to compute S (-1)" for the value of N you found. What can you say about your answer n! n=0 compared to the decimal expansion of e ? (We will see later that e-' is the actual value of L)

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