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Posted on Sep 29, 2024

3. Pores (n=400000) in a capillary of thickness 0.5m and surface area 0.04cm2 have an average length of 1.5m and diameter of 2m that facilitate

3. Pores (n=400000) in a capillary of thickness 0.5m and surface area 0.04cm2 have an average length of 1.5m and diameter of 2m that facilitate the transport of molecules and fluid from the capillaries into the interstitial space at normal body temperature. A 0.2M concentration of a non-dissociating molecule of diameter 1.5 m is carried by the blood with an average velocity of 0.003ms1 to this capillary for exchange. [plasma viscosity =1.3mPas ] a. Given that the molecule is used up in the interstitial space and the blood and interstitial fluid hydrostatic pressures are 35mmHg and 4mmHg, respectively i. Determine the effective osmotic pressure of the molecule in the blood ii. Estimate the tortuosity of the capillary wall ( 2 marks) iii. Calculate the hydraulic conductance across the membrane and the net fluid flow rate b. Estimate the solvent flux (JV) and solute flux (J8) across the membrane (8 marks) FormulaBank(allsymbolshavetheirusualcontextualmeanings):1mmHg=133Pav(r)=4LPR2[1(RT)2]0C=273K1L=1103m3LpSJ=(PCPIF)(CIF)=RPg=9.81ms2GlomerularfiltrationR=8.314/K1mol1=Kf[(PGCPBS)(GC(blood)=1060kgm3c(blood)=3770Jkg1K1)=LMRT=drdv=RTi=1Nci1V1A1=2V2A2eff=iMRTQ=A1V1=A2V2Q1=Q2+Q3=LapparentLactualF=dt2A2u2dtu21A1u1dtu1Q=LpSP=N(8tmR4)PF=Q(v2v1)P=R48LQLp=(SAp)8tmR2Jv=LpS(P) Js=Jv(1)C+PmSC=1(1ra)2Pm=(1)NpD=xMPAsDa=PaPcgarDL1=Da1+Vc1 qx=kdxdt 3. Pores (n=400000) in a capillary of thickness 0.5m and surface area 0.04cm2 have an average length of 1.5m and diameter of 2m that facilitate the transport of molecules and fluid from the capillaries into the interstitial space at normal body temperature. A 0.2M concentration of a non-dissociating molecule of diameter 1.5 m is carried by the blood with an average velocity of 0.003ms1 to this capillary for exchange. [plasma viscosity =1.3mPas ] a. Given that the molecule is used up in the interstitial space and the blood and interstitial fluid hydrostatic pressures are 35mmHg and 4mmHg, respectively i. Determine the effective osmotic pressure of the molecule in the blood ii. Estimate the tortuosity of the capillary wall ( 2 marks) iii. Calculate the hydraulic conductance across the membrane and the net fluid flow rate b. Estimate the solvent flux (JV) and solute flux (J8) across the membrane (8 marks) FormulaBank(allsymbolshavetheirusualcontextualmeanings):1mmHg=133Pav(r)=4LPR2[1(RT)2]0C=273K1L=1103m3LpSJ=(PCPIF)(CIF)=RPg=9.81ms2GlomerularfiltrationR=8.314/K1mol1=Kf[(PGCPBS)(GC(blood)=1060kgm3c(blood)=3770Jkg1K1)=LMRT=drdv=RTi=1Nci1V1A1=2V2A2eff=iMRTQ=A1V1=A2V2Q1=Q2+Q3=LapparentLactualF=dt2A2u2dtu21A1u1dtu1Q=LpSP=N(8tmR4)PF=Q(v2v1)P=R48LQLp=(SAp)8tmR2Jv=LpS(P) Js=Jv(1)C+PmSC=1(1ra)2Pm=(1)NpD=xMPAsDa=PaPcgarDL1=Da1+Vc1 qx=kdxdt