3) The electric generator [alternator] consists of coils that rotate in a magnetic field (see figure). Due to rotation, a voltage is generated in the circuit and it is taken to where it is required. If direct current is desired, it can be rectified, which can be done by contacts with brushes that as the coils rotate invert the current so that it always goes in the same direction (see the figure]. A) It is a simplified diagram, with a single turn in the turn. First write an equation for the magnetic field flow through the circuit when it makes an angle OR with the magnetic field [the area of the flow is the part perpendicular to the field). B} Using Faraday's Law, express the induced voltage in the circuit (before rectifying the current}. C} Suppose that the magnetic field is 0.1 T and that the coil is square. 0.1 m on the side. in addition, the circuit rotates at 60 Hz and the coil has 300 turns. Calculate the amplitude of the voltage that is generated. D) If this circuit is closed, for example, to turn on the lamp, a current I passes by itself. To maintain the rotation of the coil, then you have to exert a torque that is slightly greater than the torque of the magnetic field over the current in the coil. Indicate the expression for the torque on a circuit with current I placed in a magnetic field. E) If the lamp has a resistance of 5 ohms, calculate the current I in the circuit. Then, with Ohm's law, the electrical power used by the lamp. F) On the other hand, the mechanical power that must be passed to the generator is equal to the torque due to the angular rotation frequency. Calculate the torque in the generator and then the power in it. This power must be the same as that con5umed by the lamp. That is, mechanical energy is transformed in exactly the same way into electrical energy