$3.$ The sequential circuit with Cnt input and Y output is shown below.

a$.$ Create state diagrams and state tables of the circuit.

b$.$ Determine whether this circuit follows the Mealy or Moore model

c$.$ Create the diagram or table you created in option A with positive edge$-$triggered S$-$R Flip. Build with flops.$$

Diyagram There is an input labeled Cnt at the top left, which leads to an inverter symbol, indicating a NOT gate.

The output of the NOT gate connects to:

The first input of a three$-$input AND gate on the left side.

Through a connection that splits into two paths:

One path goes directly to the first input of a two$-$input AND gate on the right side.

The other path goes through a series of three AND gates, suggesting a cascading logical function where the second and third AND gates are interconnected, and the inputs are not explicitly shown. The output of this cascading AND gates arrangement connects to the D$1$ input of the second D flip$-$flop.

The Clk input is on the bottom left and connects to the clock inputs of both D$-$type flip$-$flops $($D$0$ and D$1).$

The first D$-$type flip$-$flop $($D$0)$ has:

A D$0$ input connected to the output of a two$-$input AND gate, which combines the inverted Q$1($from the second flip$-$flop$)$ and the Cnt input signal.

A Q$0$ output that connects to another two$-$input AND gate on the right side, combining it with the Q$1$ output of the second flip$-$flop.

An inverted Q$0\text{'}$ output $($not connected to anything else visible in the diagram$).$

The second D$-$type flip$-$flop $($D$1)$ has:

A D$1$ input connected to the output of the cascading AND gates mentioned in point $2.$

A Q$1$ output that has two connections:

Directly as one of the inputs to the two$-$input AND gate that also receives Q$0.$

Directly as one of the inputs to an OR gate on the far right side of the diagram.

An inverted Q$1\text{'}$ output $($not connected to anything else visible in the diagram$).$

The output of the two$-$input AND gate that combines Q$0$ and Q$1$ connects to the second input of the OR gate on the far right.

The output of the OR gate is labeled Y$.$