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30 0.2 m 450 N 1.5 m 2 m 1.5 m 200 N 200 N-m Figure 1 2. Consider the same general setup as

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30 0.2 m 450 N 1.5 m 2 m 1.5 m 200 N 200 N-m Figure 1 2. Consider the same general setup as in Problem 1 but with a distributed load along the beam. This distributed load is described by the function a) Sketch the free-body diagram of the beam. w(x) = KN/m. b) Replace the loading system acting on the beam with an equivalent resultant force. c) Find the point of action of the distributed force with respect to point O. d) Find the resultant moment applied at O. W W = () kN/m 9 kN/m -3 m 0 X

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