30. log, (x + 1) - log; (x2 -1) 9. log, (2x2 + x-21) -108, (x-3) 32. logs (x - 8) +10gs (x+2)-logs (x2 - x-6) 3. 1082 (12 - 4) - 1082 (x+2 ) (33. In(x2 - 81) - In(x2 -6x-27) 34. In(x2 - 5x+6) -[In(x) +In(x-3)] HW 3.1.2: Compound Interest n Compounds per year Compound Continuously A= Amount P = Principal (initial investment) A = P ( 1+") A = Pe" r = APR (annual percent rate, decimal) compairing both of them t = number of years n = number of compounds per year Do each of the bullets for Exercises 1-6. . Find the amount, A(t), in the account as a function of the term of the investment t in years. . Determine how much is in the account after 5 years, 10 years, and 30 years. Round your answers to the nearest cent. . Determine how long will it take for the initial investment to double. Round your answer to the nearest year. 075 1. $500 is invested in an account, which offers 0.75%, compounded monthly. 2. $500 is invested in an account, which offers 0.75%, compounded continuously. 3. $1000 is invested in an account, which offers 1.25%, compounded quarterly. . 0125 25 4. $1000 is invested in an account, which offers 1.25%, compounded continuously. 5. $5000 is invested in an account, which offers 2.125%, compounded daily. 1= 365 6. $5000 is invested in an account, which offers 2.125%, compounded continuously. OnRamps Unit 3 HW Page 18