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(3^(2x))-6*(3^x)=-8 Question 12: An amount of $280 is invested with a constant interest rate. After 30 years, the value of the investment has reached $1000.

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(3^(2x))-6*(3^x)=-8

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Question 12: An amount of $280 is invested with a constant interest rate. After 30 years, the value of the investment has reached $1000. Assuming that interest was compounded continuously, what was the (1 Point) nominal (annual) interest rate? O 4.24% O 4.48% O 4.32% O 4.40%

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