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37 Solve for N as a function of t, we get N = a(1-1) Some calculation details: +(1-a)) 38 Now let z = 1,
37 Solve for N as a function of t, we get N = a(1-1) Some calculation details: +(1-a)) 38 Now let z = 1, a = 0.33, b = 2.15 and t = 0.5, the N you calculated in 37 is
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Given the equation N za1 eatight b we can substitute the values z 1 a 033 b 215 and ...
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Elements Of Chemical Reaction Engineering
Authors: H. Fogler
6th Edition
013548622X, 978-0135486221
