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39. C. Q, = McAT QZEMLF Q3 = MCAT - Co-gus ) ( 2050) (25) = (0,848) ( 3 34) = (0.64) (wind (39) =
39. C. Q, = McAT QZEMLF Q3 = MCAT - Co-gus ) ( 2050) (25) = (0,848) ( 3 34) = (0.64) (wind (39) = 463. 32S ) = 282, 3LJ = 137. 6 15 2. In preparing a cold drink with a final temperature of OG, Mary mixes 50 g of ice at -10 C with some juice at +10 C. Suppose the specific heat of the juice is 4000 J/(kg.C), the specific heat of ice is 2000 J/(kg . C) and the latent heat of fusion of water and the juice are the same and is equal to 3x105 J/kg. Answer the owing questions based on the information provided. You may assume that the cup Mary us making the drink insulates well so there is no heat loss during the mixing, i.e., SQ = 0. (a) What mass of juice should Mary add to the ice so that no ice i formed into liquid water and no liquid juice is transformed into solid juice? (b) What mass of juice should Mary add to the ice so that all the ice is just melted? 3. A 600g bar of ice is initially at -330C. The latent heat of the fusion of ice is 334 kJ/kg, the specific heat of ice is 2050 J/(kg.C), and the specific heat of water is 4180 J/(kg.C). Calculate the final temperature of the system if 383.9 kJ of energy is added. VNI
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