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4. [0.13/1 Points] PREVIOUS ANSWERS WANEFMAC7 11.2.010. ASK YOUR TEACHER PRACTICE ANOTHER The cost of producing x teddy bears per day at the Cuddly Companion
4. [0.13/1 Points] PREVIOUS ANSWERS WANEFMAC7 11.2.010. ASK YOUR TEACHER PRACTICE ANOTHER The cost of producing x teddy bears per day at the Cuddly Companion Co. is calculated by their marketing staff to be given by the formula C(X) = 100 + 44x 0.098. (a) Find the marginal cost function C'(x). C'(x) = 26 X Use it to determine how fast the cost is going up (in $) at a production level of 100 teddy bears. 35 C] per teddy bear Compare this with the exact cost of producing the 101St teddy bear (in $). The cost is increasing at a rate of $ \\/ per teddy bear. The exact cost of producing the 101St teddy bear is $ 45991 x . Thus, there is a difference of $ 24009 x (b) Find the average cost function E, and evaluate 5(100) (in $). E(x) = 48 X 5(100) = s 43 x per teddy bear What does the answer tell you? The average cost of producing the first hundred teddy bears is 3; x per teddy bear. Need Help? Rndll Mann U|EP MY UTEP X Content X VA 11.2 Homework-First Application X + C webassign.net/web/Student/Assignment-Responses/last?dep=31170767#Q4 M Gmail YouTube Maps Question 45 - HW... C lem #16 of 22 Inve... Question 9 - HW I... Q 5. [-/1 Points] DETAILS WANEFMAC7 11.2.011. MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER Assume that it costs a company approximately C(x) = 400,000 + 140x + 0.001x2 dollars to manufacture x smartphones in an hour. (a) Find the marginal cost function. Use it to estimate how fast the cost is increasing when x = 10,000. $ per smartphone Compare this with the exact cost of producing the 10,00ist smartphone. The cost is increasing at a rate of $ per smartphone. The exact cost of producing the 10,001st smartphone is $ . Thus, there is a difference of $ (b) Find the average cost function C and the average cost to produce the first 10,000 smartphones. C (x ) = C(10,000) = $ (c) Using your answers to parts (a) and (b), determine whether the average cost is rising or falling at a production level of 10,000 smartphones. The marginal cost from (a) is ---Select--- |than the average cost from (b). This means that the average cost is ---Select--- at a production level of 10,000 smartphones. Need Help? Read It Watch It 6. [-/1 Points] DETAILS WAS WANEFMAC7 11.2.012.MI. MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER Assume that it costs a company approximatelyW7 MYUTEP X ' a Content X W' 11.2 Homework-FirstApplicai X + v 6 C' i webassign.net/web/Student/Assignmeni-Responses/Iast?dep:31170767#Q4 [I] '5? 3 I] o E ASK YOUR TEACHER PRACTICE ANOTHER M Gmail II YouTube 0 Maps 6 Question 45-HW.., G lem #16 of 22lnve... e QuestionQHWI... Q WAS WANEFMAC711.2.012.MI. 6. [/1 Points] Assume that it costs a company approximately C(X) = 800,000 + 280x + 0.0005X2 dollars to manufacture X game systems in an hour. (a) Find the marginal cost function C'(x). C'(x) = Use it to estimate how fast the cost is increasing when x = 60,000. $ :] per game system Compare this with the exact cost of producing the 60,0015t game system. The cost is increasing at the rate of $ :] per game system. The exact cost of producing the 60,0015t game system is $ [: . The actual cost of producing the 60,001st game system is -Seleci- v the estimated cost of producing the 60,0015t game system found using the marginal cost function. (b) Find the average cost function E(x) and the average cost to produce the rst 60,000 game systems. (Round your answer to the nearest cent.) Em ll E(so,000) : (c) Using your answers to parts (a) and (b), determine whether the average cost is rising or falling at a production level of 60,000 game systems. The marginal cost from (a) is Select v the average cost from (b). This means that the average cost is at a production IEVEI Of 50,000 game systems. ll 4- Need Help? lam-m 7. [/1 Points] WANEFMAC711.2.014. ASK YOUR TEACHER PRACTICE ANOTHER U|EP MY UTEP X Content X VA 11.2 Homework-First Applicatic X + C webassign.net/web/Student/Assignment-Responses/last?dep=31170767#Q4 M Gmail YouTube Maps Question 45 - HW... C lem #16 of 22 Inve... Question 9 - HW I... 7. [-/1 Points] DETAILS WANEFMAC7 11.2.014. MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER The Audubon Society at Enormous State University (ESU) is planning its annual fund-raising "Eatathon." The society will charge students $1.10 per serving of pasta. The society estimates that the total cost of producing x servings of pasta at the event will be C(x) = 370 + 0.10x + 0.002xdollars. (a) Calculate the marginal revenue R'(x) and profit P'(x) functions. R' ( X ) = P' ( X ) = (b) Compute the revenue and profit, and also the marginal revenue and profit, if you have produced and sold 200 servings of pasta (in $). revenue $ profit to marginal revenue per additional plate marginal profit per additional plate Interpret the results. The approximate ---Select--- |from the sale of the 201st plate of pasta is $ (c) For which value of x is the marginal profit zero? X = plates Interpret your answer. The graph of the profit function is a parabola with a vertex at x = , so the loss is at a minimum when you produce and sell plates. Need Help? Read ItU|EP MY UTEP X Content X VA 11.2 Homework-First Applicatic X + C webassign.net/web/Student/Assignment-Responses/last?dep=31170767#Q4 M Gmail YouTube Maps Question 45 - HW... C lem #16 of 22 Inve... Question 9 - HW 1... 8. [-/1 Points] DETAILS WANEFMAC7 11.2.015. MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER Suppose P(x) represents the profit on the sale of x Blu-ray discs. If P(1,000) = 2,000 and P'(1,000) = -6, what do these values tell you about the profit? P(1,000) represents the profit on the sale of Blu-ray discs. P(1,000) = 2,000, so the profit on the sale of Blu-ray discs is $ . P'(x) represents the -----Select--- ---- vas a function of x. P'(1,000) = -6, so the profit is decreasing at the rate of $ per additional Blu-ray disc sold. Need Help? Read It 9. [-/1 Points] DETAILS WANEFMAC7 11.2.019. MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER Assume that the demand function for tuna in a small coastal town is given by p = 24,000 1.5 (200
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