4. [-/10 Points] DETAILS SERPSE10 10.3.OP.009. MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER The figure below shows the drive train of a bicycle that has wheels 67.3 cm in diameter and pedal cranks 17.5 cm long. The cyclist pedals at a steady cadence of 78.5 rev/min. The chain engages with a front sprocket 15.2 cm in diameter and a rear sprocket 7.00 cm in diameter. Rear sprocket Pedal crank `Front sprocket Chain (a) Calculate the speed of a link of the chain relative to the bicycle frame. m/s (b) Calculate the angular speed of the bicycle wheels. rad/s (c) Calculate the speed of the bicycle relative to the road. m/'s (d) What piece of data, if any, are not necessary for the calculations? O diameter of front sprocket O diameter of wheels O angular rate O length of pedal cranks O diameter of rear sprocket O none of these Need Help? Read It Watch It 5. [-/10 Points] DETAILS SERPSE10 10.3.OP.010.MI.SA. MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive any points for the skipped part, and you will not be able to come back to the skipped part. Tutorial Exercise A wheel 1.77 m in diameter lies in a vertical plane and rotates about its central axis with a constant angular acceleration of 4.52 rad/s'. The wheel starts at rest at t = 0, and the radius vector of a certain point P on the rim makes an angle of 57.30 with the horizontal at this time. At t = 2.00 s, find the following. (a) the angular speed of the wheel (b) the tangential speed of the point (c) the total acceleration of the point P (d) the angular position of the point P Click here to begin! Need Help? Read It 6. [-/10 Points] DETAILS SERPSE10 10.3.P.011. MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER A car accelerates uniformly from rest and reaches a speed of 21.0 m/s in 9.04 s. Assume the diameter of a tire is 58.8 cm. (a) Find the number of revolutions the tire makes during this motion, assuming that no slipping occurs. rev (b) What is the final angular speed of a tire in revolutions per second? rev/s Need Help? Read It Watch It1. [-/10 Points] DETAILS SERPSE10 10.1.OP.002. MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER During a certain time interval, the angular position of a swinging door is described by 0 = 5.07 + 9.8t + 2.08t2, where 0 is in radians and t is in seconds. Determine the angular position, angular speed, and angular acceleration of the door at the following times. (a) t = 0 0 = rad w = ad/s a= rad/s2 (b) t = 3.01 s rad rad/s rad/s2 Need Help? Read It Watch It 2. [-/10 Points] DETAILS SERPSE10 10.2.OP.004.MI.SA. MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive any points for the skipped part, and you will not be able to come back to the skipped part. Tutorial Exercise An electric motor rotating a workshop grinding wheel at 1.01 x 102 rev/min is switched off. Assume the wheel has a constant negative angular acceleration of magnitude 2.05 rad/s2. (a) How long does it take the grinding wheel to stop? (b) Through how many radians has the wheel turned during the time interval found in part (a)? Click here to begin! Need Help? Read It 3. [-/10 Points] DETAILS SERPSE10 10.2.OP.005. MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER A rotating wheel requires 2.94-s to rotate through 37.0 revolutions. Its angular speed at the end of the 2.94-s interval is 97.9 rad/s. What is the constant angular acceleration of the wheel? rad/s2 Need Help? Read it Watch It