4. [16 marks] Integer Multiplication I. a) Multiply the following two 10-bit binary natural numbers. The multiplicand is 10011 11100 (27c hex) and the multiplier is 11010 (1a hex). Show, in hexadecimal, i) the initial value of the accumulator, ii) each term added to the accumulator _and_ the resulting partial sum. The last addition yields the final result. b) Redo the multiplication steps exactly as in question 4 a), but initialize the accumulator to s = 11011 (1b hex) instead of 0. Show the same intermediate and final values. (This is called "fused multiply-add"). 

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