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4- 2 HKE) = H2 (g) - g) In the above reaction. 3 moles of HI (g) are placed in a constant volume vessel

4- 2 HKE) = H2 (g) - g) In the above reaction. 3 moles of HI (g) are placed in a constant volume vessel under 12 atmospheric pressure. When equilibrum is reached at constant temperature. what will be the partial pressure of HI (g) If mol fraction of H2 is 1/67 4 atm. b) 1 atm. 6 atm d) 8 atm. 3 atm Bos birak

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