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(4) (8 pts) Given a positive integer n that is a perfect square (i.e. its square root is an integer: for example, n=25 ), present
(4) (8 pts) Given a positive integer n that is a perfect square (i.e. its square root is an integer: for example, n=25 ), present an algorithm to output square root of n. Your algorithm needs to run in O(logn) time. Obviously, you cannot invoke any predefined function to compute the square root. Hint: You want to search for n in 122(n1)n. A note on style The following is the pseudo-code I will write for the problem of finding the number of even integers in A[p] through A[r]. You may use this as guideline. Number-of-Even (A, p,r) count =0; // scan the entries and find how many are even for i=p to r if (A [i] is even) count = count +1;// or, count++; return count; The above is only to give you an idea of suggested style. In reality, in the future, the following is acceptable so long as you claim a complexity of O(r p+1) count = number of even entries in A[p]A[r]
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