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4. Assume an electron has a de Broglie wavelength of A. The value of A (in pm) is given by 2 = (xy +1) pm
4. Assume an electron has a de Broglie wavelength of A. The value of A (in pm) is given by 2 = (xy +1) pm where xy are the last two digits of your SID number! (e.g. if your SID is 530882405, xy = 05 and A = 6.0 pm). These are wavelengths comparable to x-rays. Calculate (a) the magnitude of the electron's momentum pe. (b) the electron's kinetic energy Ke in joules. (c) the electron's kinetic energy Ke in kev (not eV). If your calculated energy was the energy of a photon rather than an electron, what would be the wavelength of the photon
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