4. In each of the following parts, find the equation of the line... a. ...that passes through the points (-2, -1) and (4,1) b. Equation of line: ... that has an x intercept at x = 2, and is perpendicular to the line 3y-6x=-12 c. ...that passes through the points (3,-1) and (3,4) Equation of line: Equation of line: 2 5. Find the equation of the blue line from the graph below: 6. First, put the linear equation below into the form y = mx + b by solving for y. Then, calculate x and y intercepts. Finally, graph the equation, labelling the intercepts. 3y-2x 3 2 + = 1 3 y = mx + b form: x intercept: y intercept: