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4. Oil Bearing Consider the oil bearing in the following diagram. Oil ( = 0.08 Pas, p = 850 kg/m) is at a high
4. Oil Bearing Consider the oil bearing in the following diagram. Oil ( = 0.08 Pas, p = 850 kg/m) is at a high pressure inside the circular cross section channel inside the load block. Due to the higher pressure, the oil is squeezed out of the circular cross section reservoir and under the load block where it forms a gap between the load block and the bearing surface. In this problem the load block and bearing surface are both stationary, and the oil flows in a thin layer from the center to the sides. A constant gap height is maintained through which oil flows between the base and the bearing. Assume that the length of the bearing (into the page) is sufficiently large that the problem can be considered two-dimensional. Clearly state any additional assumptions you make and clearly illustrate your solution process. Describe critical steps and the elimination of terms in any equations. Answer the questions below the figure. Oil Load 3,000 kg/m (this is load per length) = Width 0.3m Pint = ? Load Block Oil Oil Bearing Surface hb= 0.002cm Figure 3: Diagram of the oil bearing For the questions below, start from the general governing fluid dynamics equation(s) and indicate/justify all assumptions or simplifications you make. a) Sketch the pressure distribution on the top and bottom sides of the load block. b) What is the pressure required in the oil reservoir in order to maintain the bearing height gap of hb = 0.002 cm? c) What is the mass flow rate of oil (per meter length of the bearing) that is required to maintain the bearing height gap of h = 0.002 cm? d) What is the equation for the shear stress along the bottom surface of the load block? Express your answer only in terms of given variables (no numbers).
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