(4 points) Let f(t) be the number of centimeters of runfall that has falien snce midinght, where t is the tirne in hass. Match the following statements to their interpretations given betod (a) f(5)=2.6 (b) f1(6)=7 (c) f(5)=0.5 (d) (f1)(6)=3 Interpretations: 1: at 6 nours after mianighi, 7 oentimeses of rain have falken 2: at 2.6 houss gost mineght, 5 centimeters of rain have fallen 3: When 3 centimeters thve fallen, rain is accumutating at a rate of 156 hicm, so 3 taves approximately 100 men for the fotal accumulation to go fiem 3 to 4 em 4: at 5AM, ran is fallng at a rale ot 26cmine so approxiratey 0.22cm of rain fats in the nest tive minutes 5: at 0.5 hours afer mignight, thin is faking at a rate of 5cm her, so approximatey 0.42cm of rain fats in the next five minutes 5: a 5 AM, the rain is falling at a rase of 05 cinh, 30 approximatey 0.0003 cm of ran fabs between 5AM and 5.01AM Ti when 3 centimeters of rien have tallen, rain B tallng at a rate of 6 cminr, so it takes approximatey 100 min for the tolat accuimulition to go from 4 fo 4 cm 6: 0.5 centirnetess of rain have tallen o nours aner midnight 9: when 3 centimeters have falen, ram is accurzulating at a rate of 1/6 cmhe, so it takes approxinaley 36 ifin for the total accumulation to go from 3 lo 31 cas 10: al 6 tours after midnght, rain is failng at a rate of 3cinhr, so approkmatey 060cm of tain fa0s in the next ten munutes 11: at 3 hours uper midakin, ran is fiang an a rage of 6 cmhe, so approxmately 100cm of rain favi between 3AM and 30AM 12. at 5MM,26 centimeless of iast have talken 14: a4 5 hours atter midighi, 0 fortineters of eian have falken 15: when 6 centimeters of ran have fatken it is accuimitating at a fate of 10 cmhr, so at takes approximatey 14 min for the total accianulatoon tis go from 6 to fo 1 cin 16: 6 censimeless of ran nave faten / nours afher madrignt