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4 The total force (in 1N) on the circular end of a water tank is F = 15,5001y1/ 16 - y2 dy. Evaluate F. 0

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4 The total force (in 1N) on the circular end of a water tank is F = 15,5001y1/ 16 - y2 dy. Evaluate F. 0 The total force (in N) on the circular end of a water tank is [:I. (Simplify your answer. Type an integer or decimal rounded to one decimal place as needed.)

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