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4. The velocity of a skydiver (in m/s) t seconds after jumping from the plane is v(t) = 500(1 - e-kt/100 )/k, where k is

4. The velocity of a skydiver (in m/s) t seconds after jumping from the plane is v(t) = 500(1 - e-kt/100 )/k, where k is a constant. The terminal velocity of the skydiver is the value that v(t) approaches as t becomes large. Graph v with k = 20 and estimate the terminal velocity. (Hint: You need to observe values of the function when t is "large". This may require you to change your window or graph settings to allow for larger values of t in order to see the eventual terminal velocity value.)

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