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4). We have benzene (A) and methylbenzene (B) in a distillatory (a container where the liquid and vapor are in equilibrium), but we do not
4). We have benzene (A) and methylbenzene (B) in a distillatory (a container where the liquid and vapor are in equilibrium), but we do not know the ratio of these two materials. The total pressure of the system is 760mmHg(1mmHg=133.322Pa). The vapor pressures of pure A and B satisfy the Antoine equation: logPA0=6.89704T+220.2371206.350logPB0=6.95334T+219.3771343.943 where PA0(mmHg) and PB0(mmHg) are the vapor pressures of pure benzene and pure methylbenzene, and T(C) is the temperature in the system. a) Assume this is an ideal system (ideal solution and ideal gas). Using Raoult's law and Dalton's law calculate the mole fraction of A and B in the liquid and in the vapor at T= 92C and T=100C b) For the total pressure given above compute values of xA and yA for different values of T using a spreadsheet and Raoult's law and Dalton's law. Then plot the values of T vs. xA (mole fraction of benzene in the liquid), T vs. yA (mole fraction of benzene in the vapor), and xA vs. yA for the total pressure given above. Find the conditions under which the system only has benzene. Find the conditions under which the system only has methylbenzene
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