4.1 0.24y 0.1 -4 fi(x) 1x+6 - x-10 -10 70 As shown in the given graph of f (2) - (ve+) -4) (= - 10) there is a hole at x = 10. /Joe is trying to find lim,_+10 f (x). He begins by multiplying by the conjugate : lim $10 (/(240) -4) ((+6)+4) (=-10) (V(=+6)+4) Using FOIL, he multiplies the numerator to get: lime ((+6) -16)If you simplify further, what is the result: (2 -10) liz +10 Illery (= (= + 6) + 4x-10,/(# +6)-401 which can then be computed as ents (10 -10) ns (10-,(10 + 6) + 4-10 -10. (10 + 6)- 40) (0) (10.V/16 + 40 -10)10-40) which DNE The problem can not be simplified any further than what Joe already accomplished, and so the final limit DNE. lim -10 ( 10) (E -10).(/( + 0) + 4) lime -10 which can then be computed as (10-8 +4) (V16 + 4)