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4-c) Two sample proportion summary hypothesis test: P1 : proportion of successes for population 1 P2 : proportion of successes for population 2 P1 -
4-c) Two sample proportion summary hypothesis test: P1 : proportion of successes for population 1 P2 : proportion of successes for population 2 P1 - P2 : Difference in proportions Ho : P1 - P2 = 0 HA : P1 - P2 7 0 Hypothesis test results: Difference Count1 Totall Count2 Total2 Sample Diff. Std. Err. Z-Stat P-value P1 - P2 28 100 32 100 -0.04 0.064807407 -0.6172134 0.5371 Fail to reject the null hypothesis and conclude that there is not sufficient evidence to prove that there was a difference in the proportion of households with under $50,000 income between Edmonton and Calgary. Under the null hypothesis, the test statistic follows a z-distribution and the expected difference between the two properties is zero. Since, the p-value is greater than 0.05, we fail to reject the null hypothesis and conclude that there is no sufficient evidence to support the claim that there was a difference in the proportion of households with under $50,000 income between Edmonton and Calgary. 4-d) Contingency table results: Rows: Recode(Income) Columns: City Calgary Edmonton Total 1 28 32 60 2 and 3 72 68 140 Total 100 100 200 Chi-Square test: Statistic DF Value P-value Chi-square 0.38095238 0.53714-f) Contingency table results: Rows: Income Columns: City Calgary Edmonton Total $100,000 and over 36 32 68 $50,000 to $99,999 36 36 72 Under $50,000 28 32 60 Total 100 100 200 Chi-Square test: Statistic DF Value P-value Chi-square 2 0.50196078 0.778
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