$50\frac{Mg}{\text{d}\text{a}\text{y}}$ ethyl acetate from ethanol and acetic acid should be produced. The reaction is described by the equation:

$C_2{H}_{5}OH+C{H}_3$COOH$=C{H}_3$COO $C_2{H}_5+H_{2}O$

$A+B=C+D$

Reaction rate in the liquid phase is defined by the expression:

$r=k(c_A{c}_B-\frac{c_C{c}_D}{K_C})$

Reaction rate constant equals $k=7\mathrm{.}93*{10}^{-6}[\frac{m^3}{\text{k}\text{m}\text{o}\text{l}*s}]$ and the equilibrium constant equals $K_C=2\mathrm{.}93.$ The raw material is as follows $(\%$ mass$)$: $u_{A0}=46\%,u_{B0}=23\%,u_{D0}=31\%.$ The reaction

should be carried out to ${}_B=0\mathrm{.}35.$ We assume constant density of the mixture equals $1020\frac{kg}{m^3}.$ Calculate CSTR reactor volume which is necessary to obtain the amount of ethyl acetate.

$($Please$,$ do not change the names of given variables and only use the variables whose values are given in the question. Thanks in advance :$))$