5 10 points eBook Hint Print An analysis of variance experiment produced a portion of the accompanying ANOVA table. Assume normality in the underlying populations. (You may find it useful to reference the Ftable.) picture Click here for the Excel Data File a. Specify the competing hypotheses in order to determine whether some differences exist between the population means. = = = HD; HA: Not all population means are equal. HC HD: HA: Not all population means are equal. OHO: HA HB HC OHO: HAHB OHO: HA SHB HC HD; HA: Not all population means are equal. b. Fill in the missing statistics in the ANOVA table. (Round "MS" to 4 decimal places and "P" to 3 decimal places.) ANOVA Source of Variation SS df MS F p-value References Between Groups 12.66 3 0.0556 Within Groups 91.54 58 Total 104.20 61 S A survey finds that the cost of long-term care in the United States varies significantly, depending on where an individual lives. An economist collects data from the five states with the highest annual costs (Alaska, Massachusetts, New Jersey, Rhode Island, and Connecticut), in order to determine if his sample data are consistent with the survey's conclusions. The economist provides the following portion of the ANOVA table: a. Specify the competing hypotheses to test whether some differences exist in the mean long-term care costs in these five states. Book O Ho HAlaska HMassachusetts HNew Jersey O Ho: HAlaska HMassachusetts > HNew Jersey O Ho: HAlaska HMassachusetts HNew Jersey Print HRhode Island HConnecticut HA: Not all population means are equal. HRhode Islands HConnecticut HA: Not all population means are equal. HRhode Island HConnecticut HA: Not all population means are equal. ferences b. Complete the ANOVA table. Assume that long-term care costs are normally distributed. (Round "MS" to 4 decimal places and "P" to 3 decimal places.) ANOVA Source of Variation SS df MS F p-value Between Groups Within Groups 635.0542 253.2192 4 0.000 20 Total 888.2734 24