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5. [24 pts] Suppose Kosta Enterprises and Tran, Inc both go public and the initial value of one share of stock for both companies is
5. [24 pts] Suppose Kosta Enterprises and Tran, Inc both go public and the initial value of one share of stock for both companies is $26.35. Below are the graphs of the instantaneous rate of change in the value of one share of stock, where kost(t) represents the rate of change (dollars per day) for Kosta Enterprises and tran(t) represents the rate of change for Tran, Inc. KE(t) and TI(t) represents the value of one share of Kosta Enterprises and Tran, Inc., respectively. kost(t) 0.5 dollars per day tran(t) 0.5 5 6 7 8 9 10 days (a) [4 pts] Determine the value of TI(4). (b) [4 pts] For OS/$10 , find the value of t when KE(t) is the largest? t = (c) [4 pts] For > 1, determine when KE(1) = KE(1). t= (d) [4 pts] Determine [ tran(1)dt . [, tran (1)dt = (e) [4 pts] On the graph, indicate/highlight the graphical interpretation of [, kost (1) - tran (t) dt . (f) [4 pts] Which stock has the greater value at t = 10? (Note reasoning to get points.)
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